14y^2-14y-22=0

Solution for 14y^2-14y-22=0 equation:

14y^2-14y-22=0

a = 14; b = -14; c = -22;
Δ = b2-4ac
Δ = -142-4·14·(-22)
Δ = 1428
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1428}=\sqrt{4*357}=\sqrt{4}*\sqrt{357}=2\sqrt{357}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{357}}{2*14}=\frac{14-2\sqrt{357}}{28}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{357}}{2*14}=\frac{14+2\sqrt{357}}{28}
$